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use example mnemonics, fix in Examples async_target and task_dep
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@ -43,6 +43,12 @@ vectors point to the correct local storage, of the space that was not freed in t
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directive. At the end of the second \code{target} region, the data in array \plc{p} is copied back
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directive. At the end of the second \code{target} region, the data in array \plc{p} is copied back
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to the host since \plc{p} is not an allocatable array.
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to the host since \plc{p} is not an allocatable array.
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A \code{depend} clause is used in the \code{task} directive to provide a wait at the beginning of the second
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\code{target} region, to insure that there is no race condition with \plc{v1} and \plc{v2} in the two tasks.
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It would be noncompliant to use \plc{v1} and/or \plc{v2} in lieu of \plc{N} in the \code{depend} clauses,
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because the use of non-allocated allocatable arrays as list items in the first \code{depend} clause would
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lead to unspecified behavior.
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\fexample{async_target}{2f}
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\fexample{async_target}{2f}
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@ -439,9 +439,9 @@
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}{
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}{
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\def\cname{#1.#2}
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\def\cname{#1.#2}
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% Use following line for old numbering
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% Use following line for old numbering
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\def\ename{\thechapter.#2}
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% \def\ename{\thechapter.#2}
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% Use following for mneumonics
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% Use following for mneumonics
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% \def\ename{\escstr{#1}.#2}
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\def\ename{\escstr{#1}.#2}
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}
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}
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\noindent
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\noindent
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\textit{Example \ename}
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\textit{Example \ename}
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@ -39,5 +39,6 @@ void vec_mult(float *p, int N, int dev)
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free(v1);
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free(v1);
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free(v2);
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free(v2);
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}
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}
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#pragma omp taskwait
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output(p, N);
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output(p, N);
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}
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}
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@ -10,7 +10,7 @@
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integer :: i, idev
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integer :: i, idev
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!$omp declare target (init)
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!$omp declare target (init)
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!$omp task shared(v1,v2) depend(out: v1,v2)
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!$omp task shared(v1,v2) depend(out: N)
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!$omp target device(idev) map(v1,v2)
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!$omp target device(idev) map(v1,v2)
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if( omp_is_initial_device() ) &
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if( omp_is_initial_device() ) &
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stop "not executing on target device"
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stop "not executing on target device"
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@ -21,7 +21,7 @@
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call foo() ! execute other work asychronously
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call foo() ! execute other work asychronously
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!$omp task shared(v1,v2,p) depend(in: v1,v2)
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!$omp task shared(v1,v2,p) depend(in: N)
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!$omp target device(idev) map(to: v1,v2) map(from: p)
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!$omp target device(idev) map(to: v1,v2) map(from: p)
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if( omp_is_initial_device() ) &
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if( omp_is_initial_device() ) &
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stop "not executing on target device"
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stop "not executing on target device"
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@ -34,6 +34,7 @@
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!$omp end target
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!$omp end target
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!$omp end task
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!$omp end task
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!$omp taskwait
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call output(p, N)
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call output(p, N)
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end subroutine
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end subroutine
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@ -13,7 +13,10 @@ C[N][N] )
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for (i = 0; i < N; i+=BS) {
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for (i = 0; i < N; i+=BS) {
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for (j = 0; j < N; j+=BS) {
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for (j = 0; j < N; j+=BS) {
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for (k = 0; k < N; k+=BS) {
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for (k = 0; k < N; k+=BS) {
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#pragma omp task depend ( in: A[i:BS][k:BS], B[k:BS][j:BS] ) \
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// Note 1: i, j, k, A, B, C are firstprivate by default
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// Note 2: A, B and C are just pointers
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#pragma omp task private(ii, jj, kk) \
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depend ( in: A[i:BS][k:BS], B[k:BS][j:BS] ) \
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depend ( inout: C[i:BS][j:BS] )
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depend ( inout: C[i:BS][j:BS] )
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for (ii = i; ii < i+BS; ii++ )
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for (ii = i; ii < i+BS; ii++ )
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for (jj = j; jj < j+BS; jj++ )
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for (jj = j; jj < j+BS; jj++ )
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@ -3,19 +3,22 @@
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! @@compilable: yes
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! @@compilable: yes
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! @@linkable: no
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! @@linkable: no
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! @@expect: success
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! @@expect: success
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! Assume BS divides N perfectly
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subroutine matmul_depend (N, BS, A, B, C)
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subroutine matmul_depend (N, BS, A, B, C)
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implicit none
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integer :: N, BS, BM
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integer :: N, BS, BM
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real, dimension(N, N) :: A, B, C
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real, dimension(N, N) :: A, B, C
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integer :: i, j, k, ii, jj, kk
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integer :: i, j, k, ii, jj, kk
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BM = BS -1
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BM = BS - 1
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do i = 1, N, BS
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do i = 1, N, BS
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do j = 1, N, BS
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do j = 1, N, BS
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do k = 1, N, BS
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do k = 1, N, BS
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!$omp task depend ( in: A(i:i+BM, k:k+BM), B(k:k+BM, j:j+BM) ) &
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!$omp task shared(A,B,C) private(ii,jj,kk) & ! I,J,K are firstprivate by default
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!$omp depend ( in: A(i:i+BM, k:k+BM), B(k:k+BM, j:j+BM) ) &
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!$omp depend ( inout: C(i:i+BM, j:j+BM) )
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!$omp depend ( inout: C(i:i+BM, j:j+BM) )
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do ii = i, i+BS
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do ii = i, i+BM
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do jj = j, j+BS
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do jj = j, j+BM
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do kk = k, k+BS
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do kk = k, k+BM
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C(jj,ii) = C(jj,ii) + A(kk,ii) * B(jj,kk)
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C(jj,ii) = C(jj,ii) + A(kk,ii) * B(jj,kk)
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end do
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end do
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end do
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end do
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